There is a cage at the electron city zoo that contains both wild pigs and peacocks If there total of 30 eyes 44 feet how many each animal in cage?

Let's represent the number of pigs and peacocks in the cage as "p" and "e", respectively.

According to the given information:

Total number of eyes = 30

Total number of feet = 44

Each pig has two eyes and four feet, while each peacock has two eyes and two feet. So, we can set up the following system of equations:

2p + 2e = 30 (total number of eyes)

4p + 2e = 44 (total number of feet)

Solving this system of equations, we get:

p = 6 (number of pigs)

e = 9 (number of peacocks)

Therefore, there are 6 pigs and 9 peacocks in the cage.