A brown mouse is repeatedly mated with a white all the offspring are if two of what fraction F2 mice will be brown?

This sounds like a classic Mendelian genetics problem! Here's how to solve it:

Assumptions:

* Simple Inheritance: We're assuming that coat color is determined by a single gene with two alleles, one for brown (let's say "B") and one for white ("b").

* Dominant Allele: Brown is dominant, meaning a mouse with at least one "B" allele will have brown fur.

Solving the Problem

1. Parental Generation (P): A brown mouse (BB or Bb) is mated with a white mouse (bb).

2. First Filial Generation (F1):

* Since the white mouse can only contribute a "b" allele, all F1 offspring will inherit at least one "B" allele.

* This means all F1 offspring will be brown (Bb).

3. Second Filial Generation (F2):

* When two F1 mice (Bb) mate, there are four possible combinations of alleles:

* BB (brown)

* Bb (brown)

* Bb (brown)

* bb (white)

4. Fraction of Brown Mice:

* Out of these four possibilities, three result in a brown mouse (BB, Bb, Bb).

* Therefore, 3/4 of the F2 mice will be brown.

Answer: 3/4 (or 75%) of the F2 mice will be brown.